2w^2+5w-168=0

Solution for 2w^2+5w-168=0 equation:

2w^2+5w-168=0

a = 2; b = 5; c = -168;
Δ = b2-4ac
Δ = 52-4·2·(-168)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-37}{2*2}=\frac{-42}{4}
=-10+1/2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+37}{2*2}=\frac{32}{4}
=8
$